We use cookies. Find out more about it here. By continuing to browse this site you are agreeing to our use of cookies.
#alert
Back to search results
New

Certified Pharmacy Technician

Johns Hopkins Medicine
United States, Maryland, Columbia
5755 Cedar Lane (Show on map)
Sep 04, 2026

  • Apply

  • Refer a Friend
  • Back



Share This Page



  • Share on Facebook

  • Share on Twitter

  • Share on LinkedIn
  • Share via Email


Job Details

Requisition #:
674463

Location:
Johns Hopkins Howard County Medical Center,
Columbia,
MD 21044

Category:
Pharmacy

Schedule:
Rotating Shift

Employment Type:
Full Time


You were meant for Hopkins!

Johns Hopkins Howard County Medical Center is a private, not-for-profit, community health care provider, governed by a community-based board of trustees. As a member of Johns Hopkins Medicine, Johns Hopkins Howard County Medical Center is a 266-bed acute care facility that has been serving the community for nearly 40 years. We can offer the most advanced, innovative technology with the collaboration and teamwork typically found in a community hospital. Our exceptional employee development programs offer unlimited career growth potential.

What Awaits You?

  • Career growth and development
  • Diverse and collaborative working environment

ThePharmacyTechnicianis responsible for a variety of duties to assist in the preparation and packaging of medications, distribution and delivery of medications, supporting the maintenance of proper inventorylevels and,keeping appropriate records and documentation.

Hear from our hospital president

https://www.youtube.com/watch?v=qj5KuB34gU8

Hours:

Full time

Rotating Shift

Rotating Weekends

Location:

Howard County General Hospital

5755 Cedar Lane

Columbia MD

Requirements:

  • Requires a high school diploma or equivalent.
  • Registeredin the State of Maryland as a Pharmacy Technician.

  • Pharmacy Technician Certification Board (PTCB) certification required, or obtain PTCB certification

    within 1 year of hire.

Apply
Applied = 0

(web-665cd84569-kxzb2)